(B) Given equation: $x^{2}-3=\frac{2}{x}$Multiply both sides by $x$ (where $x \neq 0$):$x(x^{2}-3) = 2$$x^{3}-3x = 2$Rearranging the terms to standard

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No,it is not a quadratic equation.

(B) Given equation: $x^{2}-3=\frac{2}{x}$Multiply both sides by $x$ (where $x \neq 0$):$x(x^{2}-3) = 2$$x^{3}-3x = 2$Rearranging the terms to standard form:$x^{3}-3x-2 = 0$Here,the highest power (degree) of the variable $x$ is $3$.$A$ quadratic equation must have a degree of $2$.Since the degree is $3$,the given equation is a cubic equation,not a quadratic equation.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

Easy

Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

A
Yes,it is a quadratic equation.
B
No,it is not a quadratic equation.
C
It is a linear equation.
D
It is a cubic equation.

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Mix Examples - Quadratic Equations

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Easy

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Medium

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Easy

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Obtain the roots of the following quadratic equation by using the general formula for the solution: $25x^2 + 20x + 7 = 0$.

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Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

Similar Questions

Examine whether the following equation is quadratic or not: $(x+2)^{3} = x(x^{2}-1)$

If the roots of the following quadratic equation exist,find them by the method of completing the square: $\frac{2}{x^{2}}-\frac{1}{x}=6$.

Verify whether the given value of $x$ is a solution of the quadratic equation or not: $\frac{x+1}{x-1} - \frac{x-1}{x+1} = \frac{5}{6}, x = 5$

While selling a pen for Rs. $24$, the loss percentage is equal to its cost price in rupees. Find the cost price of the pen.

Obtain the roots of the following quadratic equation by using the general formula for the solution: $25x^2 + 20x + 7 = 0$.

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